How do you identify the 10th term of the sequence 2, -8, 32?

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Answer 1 · 2017-12-12T09:03:13

#-524288#

#2,-8,32,..#

consider adjacent terms

#32/(-8)=(-8)/2=-4#

so we have a GP common ratio #r=-4#

for a GP the nth term

#nth=ar^(n-1)#

#10th =2(-4)^9#

#=-524288#