Question

How do you simplify `frac { - 3a b ^ { - 3} c ^ { 2} } { 12a ^ { - 2} b ^ { - 4} c ^ { 5} }`?

Answer 1

`-1/4a^3bc^-3`

Explanation:

`(-3ab^-3c^2)/(12a^(-2)b^(-4)c^5)`

case by case

`a/a^(-2)=a^(1-(-2))=a^3`
Similarly
`b^-3/b^-4=b`
`c^2/c^5=c^-3`

finally

`-1/4a^3bc^-3`