How do you solve #0.2n + a = 8( 0.4n - 1)#?

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Answer 1 · 2017-12-12T15:31:38

#n=1/3(a+8)#

#0.2n+a=8(0.4n-1)#

or

#0.2n+a=3.2n-8#

or

#3.2n-0.2n=8+a#

or

#3n=8+a#

or

#n=1/3(a+8)#