How do you evaluate #(1+ 3^ { 2} ) \div 2\cdot 3^ { 2}#?

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Answer 1 · 2017-12-13T01:14:49

45

You would want to follow the order of operations BEDMAS (Bracket, exponent, division, multiplication, addition, subtraction.)

Let's start by solving what's in the brackets, so

#(1+3^2)÷2*3^2#

#= (1+9)÷2*3^2#

#(10)÷2*3^2#

Next, we can solve for the exponents

#(10)÷2*3^2#

#= 10÷2*9#

Since we see the division prior to the multiplication, we have to solve that portion first.

# 10÷2*9#

#= 5*9#

Now all we have left is to multiply.

# 5*9#

#=45#

Answer 2 · 2017-12-13T01:15:59

#5/9#

# = (1+3^2)/(2*3^2)#

# = 1/(2*3^2) + 3^2/(2*3^2)#

# = 1/(2*3^2) + 1/2#

# = (1/2) *(1/3^2 + 1)#

# = (1/2) *(1/9 + 1)#

# = (1/2) *((1+9)/9)#

# = 10/(2*9)#

# = 5/9#