How do you evaluate (1+ 3^ { 2} ) \div 2\cdot 3^ { 2}?

2 Answers
Dec 13, 2017

45

Explanation:

You would want to follow the order of operations BEDMAS (Bracket, exponent, division, multiplication, addition, subtraction.)

Let's start by solving what's in the brackets, so

(1+3^2)÷2*3^2

= (1+9)÷2*3^2

(10)÷2*3^2

Next, we can solve for the exponents

(10)÷2*3^2

= 10÷2*9

Since we see the division prior to the multiplication, we have to solve that portion first.

10÷2*9

= 5*9

Now all we have left is to multiply.

5*9

=45

Dec 13, 2017

5/9

Explanation:

= (1+3^2)/(2*3^2)

= 1/(2*3^2) + 3^2/(2*3^2)

= 1/(2*3^2) + 1/2

= (1/2) *(1/3^2 + 1)

= (1/2) *(1/9 + 1)

= (1/2) *((1+9)/9)

= 10/(2*9)

= 5/9