How do you condense $2 {log}_{2} (x + 4)$ $2log_2(x+4)$ ?

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How do you condense $2 {log}_{2} (x + 4)$ $2log_2(x+4)$ ?

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Answer 1 · 2017-12-13T08:47:25

${log}_{2} {(x + 4)}^{2}$ $log_2(x+4)^2$

Explanation:

$using the law of logarithms$ $"using the "color(blue)"law of logarithms"$

$∙ x {log x}^{n} \Leftrightarrow n log x$ $•color(white)(x)logx^nhArrnlogx$

$\Rightarrow 2 {log}_{2} (x + 4) = {log}_{2} {(x + 4)}^{2}$ $rArr2log_2(x+4)=log_2(x+4)^2$

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How do you condense $2 {log}_{2} (x + 4)$ $2log_2(x+4)$ ?

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How do you condense $2 {log}_{2} (x + 4)$ $2log_2(x+4)$ ?