How many aluminum atoms in a #0.45*mol# quantity of this metal?

1 Answer
anor277
Dec 14, 2017

#0.45*molxx"Avogadro's number"#

Explanation:

And #"Avogadro's number"-=6.022xx10^23*mol^-1#

And so there are.....

#6.022xx10^23*mol^-1xx0.45*mol~=3.0xx10^23# #"individual aluminum atoms."#

What is the mass of this number of atoms?

Related questions
Impact of this question
474 views around the world
You can reuse this answer
Creative Commons License