First, divide each side of the equation by #color(red)(8)# to eliminate the parenthesis while keeping the equation balanced:
#(8(-8 - 3x))/color(red)(8) = -136/color(red)(8)#
#(color(red)(cancel(color(black)(8)))(-8 - 3x))/cancel(color(red)(8)) = -17#
#-8 - 3x = -17#
Next, add #color(red)(8)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#color(red)(8) - 8 - 3x = color(red)(8) - 17#
#0 - 3x = -9#
#-3x = -9#
Now, divide each side of the equation by #color(red)(-3)# to solve for #x# while keeping the equation balanced:
#(-3x)/color(red)(-3) = (-9)/color(red)(-3)#
#(color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3)) = 3#
#x = 3#