Question

For the reaction N2(g)+3H2(g)--> 2NH3(g). How many moles of N2 will be need to react with exactly 1.00mol if H2?

Answer 1

`1/3` mol

Explanation:

`"N"_(2"(g)") + "3H"_(2"(g)") -> "2NH"_(3"(g)")`

From above balanced equation
1 mol of `"N"_2` requires 3 mol of `"H"_2`

So,
1 mol of `"H"_2` requires `1/3` mol of `"N"_2`