Solve for the following equation in the interval [0, 2#pi#): #3cos^2theta + sin^2theta =2#?

Question

1023 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-16T01:07:35

#theta=pi/4, (3pi)/4, (5pi)/4, (7pi)/4#

.

#3cos^2theta+sin^2theta=2#

#3cos^2theta+1-cos^2theta=2#

#2cos^2theta=1#

#cos^2theta=1/2#

#costheta=+-sqrt2/2#

#theta=pi/4, (3pi)/4, (5pi)/4, (7pi)/4#