Question

What mass of `"sodium azide"`, `Na^(+)N_3^(-)`, is required to evolve `11.3*L` of dinitrogen gas at `10^5*Pa` pressure, and `0` `""^@C`?

Answer 1

We need to represent the decomposition reaction of sodium azide...and get a mass of approx. `22*g` with respect to the salt.

Explanation:

`2NaN_3(s) rarr 2Na(s) + 3N_2(g)uarr`

This is in fact a redox reaction....sodium ion is reduced, and azide ion is oxidized to dinitrogen....

And under standard conditions of `273.15*K`, and a pressure of `10^5*Pa`, `1*mol` of Ideal Gas occupies `22.7*L`....

And `"moles of dinitrogen"=(11.3*L)/(22.7*L*mol^-1)=0.498*mol`...and we need `2/3` this molar quantity with respect to `"sodium azide."`

And thus a mass.....of `2/3xx0.498*molxx65.01*g*mol^-1~=22*g`