Question

Question #bbb9e

Answer 1

The greatest possible width of the rectangle is 10 meters.

Explanation:

Let the width be w. It is given that the length is 8 meters less than 5 times the width, so let the length be 5w-8.

The perimeter of a rectangle is the sum of twice the length and twice the width, so the perimeter will be as follows:

`2(5w-8)+2(w)`

We know that the perimeter is at most 104 meters, so to find the greatest width, we can set our perimeter equal to 104:

`2(5w-8)+2(w)=104`

We can now simplify this and solve the equation to get the maximum possible width:

`10w-16+2w=104`

`12w-16=104`

`12w=120`

`w=10`

Therefore, the maximum possible width is 10 meters.