How do you add #4 1/8+ 2 5/ 8#?

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Answer 1 · 2017-12-18T13:45:50

See a solution process below:

First, convert each mixed number into an improper fraction:

#4 1/8 = 4 + 1/8 = (8/8 xx 4) + 1/8 = 32/8 + 1/8 = (32 + 1)/8 = 33/8#

#2 5/8 = 2 + 5/8 = (8/8 xx 2) + 5/8 = 16/8 + 5/8 =(16 + 5)/8 = 21/8#

Because both fractions are over a common denominator we can rewrite the expression and add the fractions as:

#33/8 + 21/8 = (33 + 21)/8 = 54/8#

We can now convert this improper fraction into a mixed number:

#54/8 = (48 + 6)8 = 48/8 + 6/8 = 6 + 3/4 = 6 3/4#

Another process would be to rewrite the expression as:

#4 1/8 + 2 5/8 =>#

#4 + 1/8 + 2 + 5/8 =>#

#4 + 2 + 1/8 + 5/8 =>#

#6 + (1 + 5)/8 =>#

#6 + 6/8 =>#

#6 + 3/4 =>#

#6 3/4#