How do you evaluate #2\times ( 1.6- 1.4+ 8.3) \div 3#?

1 Answer
Kushagra
Dec 18, 2017

First, solve the brackets:
#2xx(1.6-1.4+8.3)div3#
Rearrange
#2xx(1.6+8.3-1.4)div3#
#color(white)(ddoiiiiii)darr#
#2xx(color(white)(ddi)9.9-1.4)div3#
#color(white)(ddoiiiiiiiiii)darr#
#2xx (color(white)(ddoiii)8.5)div3#
You get
#color(white)(ddddd)2xx(8.5)div3#
Now multiply first because if you'll divide first it'll get messy
#17div3#
As #2xx8.5=17#
Solve
#5.bar(6666)#

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