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Answer 1 · 2017-12-18T18:30:32

6.95g

The equation for the decomposition of Iron (III) oxide (#Fe_2O_3#) is;

#2Fe_2O_3->3O_2+4Fe#

We need to know how many mols of #Fe_2O_3# we have in 23.11g

#"number of mols" = "mass(g)"/"Relative Molecular Mass(g per mol)"# = #"23.11"/"159.69"# = 0.14mols

From the reaction equation, we know that 2 mols of #Fe_2O_3# decomposes to produce 3 mols of #O_2#.

Therefore 0.14mols of #Fe_2O_3# will produce 0.21mols of #O_2#

Rearrange the previously used equation.

#"mass (g)" = "number of mols"*"Relative Molecular Mass(g per mol)"# = #0.21*32# = 6.95g