How do you divide #(x ^ { 3} + 7x ^ { 2} + 7x - 15) \div ( x + 3)#?
3 Answers
Explanation:
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(x^2)(x+3)color(magenta)(-3x^2)+7x^2+7x-15#
#=color(red)(x^2)(x+3)color(red)(+4x)(x+3)color(red)(-5)(x+3)cancel(color(magenta)(+15))cancel(-15)#
#rArr"quotient "=color(red)(x^2+4x-5)," remainder "=0#
#rArr(x^3+7x^2+7x-15)/(x+3)=x^2+4x-5#
Explanation:
For the formatting for spacing I use hash color(white)("d") hash
Unfortunately the hash " " hash now fails more times than it works.
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