How do you solve #3u ^ { 2} - 5d \div 5= 0#?

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Answer 1 · 2017-12-18T23:54:51

For d:
#d=3u^2#

For u:
#u=+-sqrt(d/3)#

#3u ^ { 2} - 5d \div 5= 0#

#3u^2-(5d)/5=0#

#color(red)("Simplifying:")#

#3u^2-d=0#

-----

#color(green)("SOLVING FOR 'd':")#

#color(red)("Rearrange equation to isolate d:")#

#therefore d=3u^2#

#color(green)("SOLVING FOR 'u':")#

#3u^2=d#

#color(red)("Divide both sides by 3:")#

#u^2=d/3#

#color(red)("Take square root of both sides:")#

#therefore u=+-sqrt(d/3)#