How do you simplify #((x^-1y^3)/(x^5y^8))^3#?

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Answer 1 · 2017-12-19T06:08:12

#=> 1/ (x^18 y^15)#

#((x^-1y^3)/(x^5y^8))^3#

Rule: # (a^m)^n = a^(mn)#

#=> ((x^-3y^9)/(x^15y^24))#

Rule: #a^m/ a^n = a^(m-n)#

#=> x^(-3-15) y ^(9-24)#

#=> x^-18 y^-15#

Rule: #a^-m= 1/a^m#

#=> 1/ (x^18 y^15)#