Question

Question #541be

Answer 1

The number is `7`/

Explanation:

So, we have:
`2x-5=x+2`

If we put like terms on each side we get:
`2xcolor(red)(-x)cancel(-5color(red)(+5))=cancel(xcolor(red)(-x))+2color(red)(+5)`
`2x-x=2+5`
`x=7`

Answer 2

Let, the number be `x`
Then, double the number would be `2xxx=2x`
When you take away 5 from double the number, `2x-5` you get the number +2, so the equation will be
`2x-5=x+2`
Add 5 to both the sides
`2x-cancel5+cancel5=x+2+5`
You get
`2x=x+7`
Subtract `x` from both sides
`2x-x=cancelx-cancelx+7`
You get
`x=7`