Question #25c38

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Answer 1 · 2017-12-19T14:26:56

#x=4#

Alright, this is just a simply matter of solving for #x#.

First, subtract #x^3#

#0=x^3-64#

#0-x^3=x^3-64-x^3#

#-x^3=-64#

Next divide by #-1# to get rid of both negatives

#(cancel-x^3)/(cancel-1)=(cancel-64)/(cancel-1)#

#x^3=64#

Finally, take the cube root

#x=64^((1/3))#

#x=4#

Hope this helped!
~Chandler Dowd