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Question #eef8e

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Answer 1 · 2017-12-20T04:35:42

$\frac{x}{9^{2}} + \frac{y}{4^{2}} = 1$ $(x)/9^2+(y)/4^2=1$

Explanation:

The general equation of an ellipse is given by:
$\frac{x - h}{a^{2}} + \frac{y - k}{b^{2}} = 1$ $(x-h)/a^2+(y-k)/b^2=1$
where $2 a$ $2a$ is a major axis and $2 b$ $2b$ is a minor axis
$h = 0; k = 0$ $h = 0; k = 0$
thus with $a = 9$ $a=9$ and $b = 4$ $b=4$
by:
$\frac{x}{9^{2}} + \frac{y}{4^{2}} = 1$ $(x)/9^2+(y)/4^2=1$

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Question #eef8e

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