How do we represent #"3,3-diethyl,4-methyl,5-isopropyloctane"#?

1 Answer
anor277
Dec 20, 2017

Well first write out the octane stem....

Explanation:

#H_3stackrel(1)C-CH_2stackrel(3)CH_2stackrel(4)CH_2stackrel(5)CH_2CH_2CH_2stackrel(8)CH_3#..

Number one end, and substitute the appropriate chain positions with the alkyl groups,

#Et=C_2H_5;Pr^(i)=CH(CH_3)_2;Me=CH_3#.....

#H_3stackrel(1)C-CH_2stackrel(3)CEt_2stackrel(4)CH(Me)stackrel(5)CH(Pr^i)CH_2CH_2stackrel(8)CH_3#..

How many chiral centres does this structure contain? The numbering COULD occur from the right hand side, as we face the molecule....however, numbering from the left gives LOWER substituent numbers, and this is thus the preferred nomenclature.

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