Diamonds have a density of 3.52 g/mL. What is the volume (in units of cm3) of a diamond with a mass of 21 g?

2 Answers
Dec 20, 2017

Approx. 6*cm^3...that's a big sparkler....and I think this is the famous "Kohi-noor", the one that presently lies in QE11's crown.....

Explanation:

By definition rho_"density"="mass"/"volume"

And thus if we want volume we take the quotient....

"volume"="mass"/rho=(21*g)/(3.52*g*mL^-1)=??*mL...is this quotient dimensionally consistent? Why?

Dec 20, 2017

5.97 cm^3

Explanation:

Using the equation:
Density (gcm^(-3)) = (Mass (g)) / (Volume (cm^3)

Rearrange for volume:
Volume (cm^3) = (Mass (g)) / (Density (gcm^(-3)))

Volume = (21 g) / (3.52 gcm^(-3))

Volume = 5.97 cm^3

A note on units
cm^3 is another way of writing mL
gcm^(-3) is another way of writing g/cm^3