Question

If [OH-] = 5 * 10^-5 M then the pH will be..???

Answer 1

9.6989700043

Explanation:

`[OH^-]=5×10^-5`M
pOH = `-log [OH^-]`
pOH = `-log[5×10^-5]`
pOH = `5-log5`
pOH = `4.3010299957`
pH = `14-4.3010299957=9.6989700043`