Question

Question #2bb5c

Answer 1

`Lim_(xrarr1)lnx/(1-x)=-1`

Explanation:

`log_ex=lnx`

`Lim_(xrarr1)lnx/(1-x)=0/0`

We can use L'Hopitals rule

`Lim_(xrarr1)(1/x)/(-1)=Lim_(xrarr1)-1/x=-1/1=-1`