Given cos theta = 3/5 and theta is located in the fourth quadrant; find sin theta?
1 Answer
Dec 22, 2017
Explanation:
#"using the following "color(blue)"trigonometric identity"#
#•color(white)(x)sin^2x+cos^2x=1#
#rArrsinx=+-sqrt(1-cos^2x)#
#"since "theta" is in fourth quadrant sin will be negative"#
#rArrsintheta=-sqrt(1-(3/5)^2)#
#color(white)(rArrsintheta)=-sqrt(16/25)=-4/5#
