Question

Question #e2433

Answer 1

`1/2` times the original volume.

Explanation:

Just Recall The Combined Gas Law.

For an ideal gas,

`(P_iV_i)/T_i = (P_fV_f)/T_f`

If any work is done by or on the gas. (Well, It includes a lot of Thermodynamics.)

As per your question,

`P_f = 4P_i` (Remember the increase is three times, not the final pressure itself.)

And `T_f = 6T_i`

Putting the desired values in Places, we get,

`(P_iV_i)/T_i = (4P_i * V_f)/(6T_i)`

`rArr V_i = (4V_f)/6` (`P_i` and `T_i` get cancelled.)

`rArr V_f = (3V_i)/2`

So, Change in Volume = `DeltaV` = `V_f - V_i` = `1/2 V_i`

Hence Explained.