Question

Question #b2872

Answer 1

`351.15 K`

Explanation:

We say that kelvin is equal to celsius + `273.15`.

`C=K+273.15`

Therefore,

`78C = (78 + 273.15)K = 351.15K`

Answer 2

`=351K`

Explanation:

1. For easier conversion, better to memorize these important data than the confusing temperature scales' conversion formula.
   `"Boiling/Freezing Point of water in " C=100^o"/"0^o`
   `"Boiling/Freezing Point of water in " K=373"/"273`
2. Set up the ratio and proportion to derive the conversion formula that can be formulated from the above data. Since these two scales have same size units; thus, 100 will be cancelled out.
   `(C-0)/(100-0)=(K-273)/(373-273)`
   `(C)/cancel((100))=(K-273)/cancel((100))`
   `color(red)(C=K-273 " from " K to C` `or"`
   `color(blue)(K=C+273 " from " C to K`
3. Since these two temperature scales have different zero points and that `0^oC` corresponds to `273K`; thus, conversion requires the addition of 273 to the `C` as derived.
4. Given the value in `C`, now find the temperature to be expressed in `K`. Knowing the previously derived formula, plug in the value of `color(red)(C=78^o)`; thus,
   `K=color(red)(C)+273`
   `K=78+273`
   `K=351`
5. Therefore `78^oC=351K`