How do you use the equation given #f(x)=csc(x)# to find f '' (π/4)?

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Answer 1 · 2017-12-25T14:52:40

#pi=180°#
#pi/4=45°#
given:#f(x)=csc(x)#
#f(pi/4)=csc45°#
#f (pi/4)=sqrt (2)#
{ we know that #csc(x)=1/sin(x)# #}# & #[sin 45°=1/sqrt2]#