What effect will replacing #x# with #(x-7)# have on the graph of the equation #y=(x+4)^2#?

1 Answer
Dec 25, 2017

The graph will shift 7 places to the right

Explanation:

For the graph of an equation #y=(x+4)^2# a zero will occur at the point #x=-4# #(-4+4)^2=0^2=0#

If we use #(x-7)# instead of #x# we get #y=(x-7+4)^2-=(x-3)^2#. A zero will now occur at #x=3#, as #(3-3)^2=0^2=0#.

What you may notice is that by taking away #7# to #x#, the zeros of the graph shift by #7# to the right.

#y=(x+4)^2#, zero occurs at #-4#
#y=(x-7+4)^2-=(x-3)^2#, zero occurs at #3#

#3-(-4)=3+4=7#

#(x+4)-(x-3)=x+4-x+3=0+4+3=7#