What's the probability of rolling a 9 or higher using two fair standard dice?

2 Answers

#10/36=5/18=27.bar7%#

Explanation:

The rolls you can get with 2 six-sided dice is in this table:

#((color(white)(0),ul1,ul2,ul3,ul4,ul5,ul6),(1|,2,3,4,5,6,7),(2|,3,4,5,6,7,8),(3|,4,5,6,7,8,9),(4|,5,6,7,8,9,10),(5|,6,7,8,9,10,11),(6|,7,8,9,10,11,12))#

See that there are 10 numbers that are 9 or higher out of a total number of 36 possibilities, giving a probability of #10/36=5/18=27.bar7%#

Dec 26, 2017

total no. of outcomes# = 6×6#
favourable outcomes require that sum should be #>=9# .
favourable outcomes are
for # 9 (4,5),(5,4),(6,3),(3,6)#
for #10 (5,5),(6,4),(4,6)#
for #11 (5,6),(6,5)#
for #12 (6,6)#;
probability #=10/36=5/18~~27.7777777778%#