Question #a23ec

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Answer 1 · 2017-12-27T17:12:18

96 dB

...if by "intensity" we interpret as "sound pressure". In which case, +6 db makes it twice as intense.

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Answer 2 · 2017-12-27T18:04:42

The answer is #=93dB#

The definition of the decibel scale is

#I_(dB)=10log_(10)(I/I_0)#

where,

#I_0=1*10^(-12)#

Therefore,

If #I_(dB)=90=10log_(10)(I/I_0)#

Then,

The new decibel level will be

#I_(dB)'=10log_(10)((2I)/I_0)=10log_(10)2+10log_(10)(I/I_0)#

#10log_(10)2=10*0.3=3#

#I_(dB)'=3+90=93#