Question

What is the range of `sqrt (4-x^2)`?

Answer 1

`{yinRR|0<=y<=2}`

Explanation:

I find it is most helpful to solve the domain over which the function exists.

In this case `4-x^2>=0` which means `-2<=x<=2`

On this domain, the smallest value the function can take is zero and the largest value it can take is `sqrt(4)=2`

Hence, the the range of the function is `{yinRR|0<=y<=2}`

Hope this helps :)