How do you divide #(x ^ { 3} + 5x - 1) \div ( x - 1)#?

1 Answer
kubik98
Dec 28, 2017

#(x^3+0x^2+5x−1)/(x−1)=x^2+x+6+5/(x-1)#

Explanation:

#(x^3+0x^2+5x−1)÷(x−1)=x^2+x+6#
#(x^3-x^2)/#
#color(white)(.)0+x^2+5x-1#
#color(white)(.......)(x^2-x)/#
#color(white)(........)0+6x-1#
#color(white)(..............)(6x-6)/#
#color(white)(.................)(0+5)/#

#(x^3+0x^2+5x−1)/(x−1)=x^2+x+6+5/(x-1)#

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