A projectile is launched at an angle of 30 to the horizontal with a speed of 30 m/s. How does the horizontal component of its velocity 1.0 s after launch compare with its horizontal component of velocity 2.0 s after launch?

Question

16478 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-02T15:25:21

Component of velocity in horizontal direction #= 15sqrt3m/s#

In projectile motion, horizontal component of velocity remains constant as there is no acceleration in horizontal direction.

So, Component of velocity in horizontal direction #= vcostheta#

Component of velocity in horizontal direction #= 30xxcos30#

Component of velocity in horizontal direction #= 15sqrt3m/s#

And, horizontal component of velocity# 1.0 s# after launch is equal to its horizontal component of velocity #2.0 s# after launch.