Question

Question #fbedc

Answer 1

`Au + 3/2Cl_2 -> AuCl_3`

Explanation:

Your balanced equation was given above

`Au + 3/2 Cl_2 -> AuCl_3` This is the balanced equation.

If you have 1.25 g of gold and 1.744 g of chlorine, it means you have 0.0063 mol of gold and 0.0246 mol of `Cl_2`.

For the balanced reaction you need 197 grams of gold (which is 1 mol) and 106.5 grams of `Cl_2` (which is `3/2` mol).

Therefore `Cl_2` is in excess. The needed amount of `Cl_2` is 0.671 gram to complete the reaction provided above. The excess amount is `=1.744-0.671 = 1.073` gram.

Note that gold has an atomic weight of 197 grams and `Cl_2` has a molecular weight of 71 grams.