How do you solve #4\cdot ( x - 3) = 2x + 4#?
3 Answers
x = 8
Explanation:
Explanation:
#"distribute bracket on left side of equation"#
#rArr4x-12=2x+4#
#"subtract 2x from both sides"#
#4x-2x-12=cancel(2x)cancel(-2x)+4#
#rArr2x-12=4#
#"add 12 to both sides"#
#2xcancel(-12)cancel(+12)=4+12#
#rArr2x=16#
#"divide both sides by 2"#
#(cancel(2) x)/cancel(2)=16/2#
#rArrx=8#
#color(blue)"As a check"# Substitute this value into the equation and if both sides are equal then it is the solution.
#"left "=4(8-3)=4xx5=20#
#"right "=(2xx8)+4=16+4=20#
#rArrx=8" is the solution"#
Explanation:
Solve for
1) Clear the parentheses by distributing the 4
You can't see what the terms are until you have cleared the parentheses
After you have distributed the 4, you will have this:
2) Subtract 2x from both sides to get all the x terms together
After you have subtracted, you will get this;
3) Add 12 to both sides to isolate the
4) Divide both sides by
Answer:
................................
Check
Sub in
Solve inside the parentheses
Do both multiplications
Add