How do you solve the system of equations #x- 2y = 4# and #3x - 6y = 4#?

1 Answer
Jan 4, 2018

No solution

Explanation:

#color(white)(-)x-2y=4#

#color(white)(-)3x-6y=4#

Let's use elimination. To do that, we need to multiply the first equation by #3#

#color(white)(-)3x-6y=12#
#-#
#color(white)(-)3x-6y=4#
#-------#
#color(white)(. . .) 0x color(black)(+) 0y = 8#

hmmmm... that's strange. This could be a mistake, or this might not have a possible solution. To check, let's graph this.

Ahh, these graphs are parallel to each other. That means they have no intercepts; they never cross

So, there are no solutions