Question #dce20

1 Answer
bp
Jan 4, 2018

#=-1/3 u^(-3) +2u^(-1) +u +C#

Explanation:

#cos^5 x /sin^4 x= (1-sin^2 x)^2 cosx /sin^4 x#

Now, let sinx =u, so that cosx dx= du

Hence #int cos^5 x /sin^3 x dx= int (1-u^2)^2 / u^4 du#

#=int (u^(-4) -2 u^(-2) +1) du#

#=-1/3 u^(-3) +2u^(-1) +u +C#

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