Question #c7ff5

1 Answer
Jan 4, 2018

#x - 6 > 2x#

Explanation:

Let #x# represent the number.

1) Find the way to express the given values in terms of #x#

The number . . . . . . . . . . . . . . . #x#
6 less than the number . . . . . #x - 6#
Two times the number . . . . .#2x#

2) Write the inequality

#x - 6 > 2x# #larr# answer

.................

The problem here is that this doesn't seem to make sense.

How can a number have 6 subtracted from it, and then end up even bigger than double the number?

Suppose the number is #10#

Subtract #6# from #10#

That gives you #4#, clearly not greater than "double #10#," which is #20#.

.......................

So that is your clue that "the number" must be a negative number.

If "the number" turns out to be #- 10#, then subtracting #6# from that gives you #-16.#

And #-16# really is greater than "double #-10#," which is #- 20#

..............................

Solving the actual inequality:
#x - 6 > 2x#

Subtract #x# from both sides to get all the #x# terms together.
#- 6 > x#

So the number #x# is #-6#

It is perfectly true that #-6# is really more than #(2)("-"6)#
#(2)("-"6)# is way down at #-12#.
It's much more negative than #-6#