How do you solve #7- 4( x - 1) \geq - ( x + 1)#?

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Answer 1 · 2018-01-05T03:57:24

#x<=4#

#7-4(x-1)>=-(x+1)# #<=>#

#7-4x+4>=-x-1 <=>#

#-4x+x+7+4+1>=0 <=>#

#-3x+12>=0 <=># (#3x<=12 <=> x<=4#)

#3(4-x)>=0 <=>#

#4-x>=0# #<=>#

#x<=4#