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Answer 1 · 2018-01-05T16:09:14

#lim_(x->pi)(2+cos(x))/(x^2+1)=1/(pi^2+1)#

Given: #lim_(x->pi)(2+cos(x))/(x^2+1)#

We can plug in directly:

#=(2+cos(pi))/(pi^2+1)=(2+(-1))/(pi^2+1)=1/(pi^2+1)#

Answer 2 · 2018-01-05T16:15:27

See below

If the expression is #(2+cos(x))/(x^2+1)#

Plugging in #x=pi#

#(2+cos(pi))/((pi)^2+1)=(2+(-1))/(pi^2+1)=1/(pi^2+1)#

#:.#

#lim_(x-pi)(2+cos(x))/(x^2+1)=1/(pi^2+1)~~0.09199966836#

If this is not the right expression, then this is incorrect.