How do you find the first three iterate of the function #f(x)=2x^2-5# for the given initial value #x_0=-1#?
1 Answer
Jan 6, 2018
Explanation:
#"substitute each previous iterate into "f(x)#
#f(x_1)=2x_0^2-5=2(-1)^2-5=-3#
#f(x_2)=2x_1^2-5=2(-3)^2-5=13#
#f(x_3)=2x_2^2-5=2(13)^2-5=333#
