Mole calculation problem? (Details below)

2.43g magnesium dissolves in excess dilute hydrochloric acid. The mass of hydrated magnesium chloride #(MgCl_2ยท6H_2O)# after crystallization is...
Thanks!

1 Answer
Jan 6, 2018

We assess the reaction....

#Mg(s) + 2HCl(aq) rarr MgCl_2 +H_2(g)uarr#

...and get approx. #20*g# of hydrated salt.

Explanation:

All of our calculations depend on the given stoichiometric equation. A follow up question would be to determine the volume of dihydrogen gas evolved under given conditions.

And so ........

#"moles of magnesium"-="moles of magnesium chloride hydrate"#

#"Moles of magnesium"-=(2.43*g)/(24.31*g*mol^-1)=0.100*mol#.

And so we get #0.100*mol# #"magnesium chloride hydrate"#, the which represents a mass of....

#0.100*molxxunderbrace(203.3*g*mol^-1)_("formula mass of "MgCl_2*6H_2O)=??*g#