Question

Question #b1d24

Answer 1

`y=1/x`

Explanation:

I'm not sure exactly what "solving" a parametric equation would mean, but given `x=sec(t)` and `y=cos(t)`.

If you want to eliminate the parameter, then we can use the fact that `sec(t) = 1/cos(t)\rightarrow cos(t)=1/sec(t)`

Now, `y=cos(t) = 1/sec(t) = 1/x`, so `y=1/x`.

I hope this is what you're looking for!