A mass of #30g# of #KNO_3# was dissolved in water to give a #0.30mol*L^-1# solution. What volume of water was used?

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Answer 1 · 2018-01-07T07:53:10

Approx. #1*L#

We use the relationship...

#"Concentration"="Moles of solute"/"Volume of solution...."#

And thus we get .....#"Volume of solution"="Moles of solute"/"Concentration"#

#=((30.0*g)/(101.1*g*mol^-1))/(0.30*mol*L^-1)=1.00*1/L^-1=1/(1/L)=1.00*L#

A mass of #30*g# of #KNO_3# was dissolved in water to give a #0.30*mol*L^-1# solution. What volume of water was used?