How do you find the domain of #g(x) = x/(x^2+4)# using set-builder notation and interval notation?
1 Answer
Jan 7, 2018
Explanation:
The denominator of g(x) cannot be zero as this would make g(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.
#"solve "x^2+4=0rArrx^2=-4#
#"this has no real solutions "#
#rArrx^2+4!=0#
#"domain is "{x:x inRR}larrcolor(blue)"set-builder notation"#
#"or "(-oo,+oo)larrcolor(blue)"interval notation"#
graph{x/(x^2+4) [-10, 10, -5, 5]}