How do you find the domain of #g(x) = x/(x^2+4)# using set-builder notation and interval notation?

1 Answer
Jan 7, 2018

#(-oo,+oo)#

Explanation:

The denominator of g(x) cannot be zero as this would make g(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

#"solve "x^2+4=0rArrx^2=-4#

#"this has no real solutions "#

#rArrx^2+4!=0#

#"domain is "{x:x inRR}larrcolor(blue)"set-builder notation"#

#"or "(-oo,+oo)larrcolor(blue)"interval notation"#
graph{x/(x^2+4) [-10, 10, -5, 5]}