How do you solve #1- 2z = 1- 4z#?

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Answer 1 · 2018-01-07T21:43:02

#z = 0 #

# 1 -2z = 1 - 4z #

Collecting the #z# terms on the left:

#1-2z # # color(red)( + 4z) = 1 - 4z # #color(red)(+4z) #

#1 +2z = 1 #

Subtracting 1:

#1 # #color(orange)( - 1) + 2z = 1# #color(orange)(-1) #

#2z = 0 #

Dividing by 2:

#(cancel(2)z)/cancel(color(red)(2)) = 0/color(red)(2) #

#=> color(blue)(z= 0 ) #