What is the perimeter of a triangle with corners at #(7 ,5 )#, #(1 ,6 )#, and #(4 ,3 )#?

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Answer 1 · 2018-01-08T08:31:44

Perimeter of the triangle #P = **13.931**#

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First to find the three sides a, b, c.

#a = sqrt((6-5)^2 + (1-7)^2) = 6.0828#

#b = sqrt((4-1)^2 + (3-6)^2) = 4.2426#

#c = sqrt((7-4)^2 + (5-3)^2) = 3.6056#

Perimeter of the triangle #P = (a+ b + c) / 2#

#P = (6.0828 + 4.2426 + 3.6056) / 2 = 13.931#