What does it mean if a process is enthalpy-driven?

1 Answer
Jan 8, 2018

Consider,

#DeltaG = DeltaH - TDeltaS#

When #DeltaG<0#, the process is energetically favorable.

When a system is enthalpy driven, generally #DeltaH<0# to compensate for #DeltaS<0#. To be sure, it occurs spontaneously at lower temperatures, and nonspontaneously at higher temperatures.

Always think of that equation when considering these two variables!