How do you write the first five terms of the sequence #a_n=(-1)^n(n/(n+1))#? Precalculus Sequences Infinite Sequences 1 Answer marfre Jan 8, 2018 #-1,2, 2/3, -3/4, 4/5, - 5/6# Explanation: Given: #a_n = (-1)^n(n/(n+1))# Let #n = 1: (-1)^1(1/(1+1)) = -1/2# Let #n = 2: (-1)^2(2/(2+1)) = 2/3# Let #n = 3: (-1)^3(3/(3+1)) = -3/4# Let #n = 4: (-1)^4(4/(4+1)) = 4/5# Let #n = 5: (-1)^5(5/(5+1)) = -5/6# Answer link Related questions What is a sequence? How does the Fibonacci sequence relate to Pascal's triangle? What is the Fibonacci sequence? How do I find the #n#th term of the Fibonacci sequence? How do you find the general term for a sequence? How do find the #n#th term in a sequence? What is the golden ratio? How does the golden ratio relate to the Fibonacci sequence? How do you determine if -10,20,-40,80 is an arithmetic or geometric sequence? How do you determine if 15,-5,-25,-45 is an arithmetic or geometric sequence? See all questions in Infinite Sequences Impact of this question 1471 views around the world You can reuse this answer Creative Commons License